For the normal force in the figure to have the same magnitude at all points on t

Question

For the normal force in the figure to have the same magnitude at all  points on the vertical track, the stunt driver must adjust the speed to  be different at different points. Suppose, for example, that the track  has a radius of 3.2 m and that the driver goes past point 1 at the bottom with a speed of 14 m/s. What speed must she have at point 3, so that the normal force at the top has the same magnitude as it did at the bottom?
       m/s

For the normal force in the figure to have the same magnitude at all points on the vertical track, the stunt driver must adjust the speed to be different at different points. Suppose, for example, that the track has a radius of 3.2 m and that the driver goes past point 1 at the bottom with a speed of 14 m/s. What speed must she have at point 3, so that the normal force at the top has the same magnitude as it did at the bottom?

Explanation / Answer

Normal force at bottom = mg + m . v^2 / R = m(9.8 + 10.5^2 / 3.02)

= 46.3 m

Normal force at top = (m . v^2 / R )

Related Questions

Navigate

• Browse (All)
• Browse F
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.