HCl is added to a sample of K2CO3. 125 mL of the resulting gas is collected over
ID: 2257562 • Letter: H
Question
HCl is added to a sample of K2CO3. 125 mL of the resulting gas is collected over water at a pressure of 0.95 atm and a temperature of 25 oC. The vapor pressure of water at this temperature is 23.76 mmHg. Compute the number of moles of K2CO3in the sampleHCl is added to a sample of K2CO3. 125 mL of the resulting gas is collected over water at a pressure of 0.95 atm and a temperature of 25 oC. The vapor pressure of water at this temperature is 23.76 mmHg. Compute the number of moles of K2CO3in the sample
HCl is added to a sample of K2CO3. 125 mL of the resulting gas is collected over water at a pressure of 0.95 atm and a temperature of 25 oC. The vapor pressure of water at this temperature is 23.76 mmHg. Compute the number of moles of K2CO3in the sample
HCl is added to a sample of K2CO3. 125 mL of the resulting gas is collected over water at a pressure of 0.95 atm and a temperature of 25 oC. The vapor pressure of water at this temperature is 23.76 mmHg. Compute the number of moles of K2CO3in the sample
Explanation / Answer
2HCl + K2C03 -----> 2KCl + C02 (g ) + H20
Given total pressure =0.95 atm
Vapour pressure of water = 23.76 mm Hg
= 0.03126 atm
Pressure by C02 + vapour pressure of water = 0.95
Pressure by C02 = 0.95 - 0.03126
Pressure by C02 = 0.91874 atm
Given volume of C02 V = 125 ml = 0.125 L
n = PV/RT
= 0.91874 x 0.125 / 0.0821 x 298
n= 4.694 x 10-3 moles
Moles of C02 = 4.694 x 10-3
as 1 mole of K2C03 gives 1 mole of C02
moles of K2C03 = 4.694 x 10-3
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