I NEED ANSWER IN Kg!!!! On the planet Newtonia, a simple pendulum having a bob w
ID: 2257596 • Letter: I
Question
I NEED ANSWER IN Kg!!!!
On the planet Newtonia, a simple pendulum having a bob with mass 1.29kg and a length of 218cmtakes 1.5s , when released from rest, to swing through an angle of 12.5 ?, where it again has zero speed. The circumference of Newtonia is measured to be 5.96
I NEED ANSWER IN Kg!!!!
On the planet Newtonia, a simple pendulum having a bob with mass 1.29kg and a length of 218cmtakes 1.5s , when released from rest, to swing through an angle of 12.5 ?, where it again has zero speed. The circumference of Newtonia is measured to be 5.96
I NEED ANSWER IN Kg!!!!
On the planet Newtonia, a simple pendulum having a bob with mass 1.29kg and a length of 218cmtakes 1.5s , when released from rest, to swing through an angle of 12.5 ?, where it again has zero speed. The circumference of Newtonia is measured to be 5.96
I NEED ANSWER IN Kg!!!!
On the planet Newtonia, a simple pendulum having a bob with mass 1.29kg and a length of 218cmtakes 1.5s , when released from rest, to swing through an angle of 12.5 ?, where it again has zero speed. The circumference of Newtonia is measured to be 5.96
I NEED ANSWER IN Kg!!!!
On the planet Newtonia, a simple pendulum having a bob with mass 1.29kg and a length of 218cmtakes 1.5s , when released from rest, to swing through an angle of 12.5 ?, where it again has zero speed. The circumference of Newtonia is measured to be 5.96
I NEED ANSWER IN Kg!!!!
On the planet Newtonia, a simple pendulum having a bob with mass 1.29kg and a length of 218cmtakes 1.5s , when released from rest, to swing through an angle of 12.5 ?, where it again has zero speed. The circumference of Newtonia is measured to be 5.96
Explanation / Answer
T = 2*pi*sqrt(L/g)
1.5 = 2*3.14*sqrt(2.18/g)
g = 38.1786 m/s^2
g = GM/R^2
M = g*R^2/G = (38.1786*(5.96*10^4*10^3)^2)/(6.67*10^-11) = 2.0332e+27 kg
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