**I know that I am going to use a Kinematics equation but I cant figure out wher
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Question
**I know that I am going to use a Kinematics equation but I cant figure out where the last piece of information comes from to work the problem..I know that I have initial Velocity (25.9) and In the Y- direction acceleration of -9.8m/s. Can someone please show me how to work out this problem and where the last piece of information is coming from??
A golfer imparts a speed of 25.9 m/s to a ball, and it travels the maximum possible distance before landing on the green. The tee and the green are at the same elevation.
**I know that I am going to use a Kinematics equation but I cant figure out where the last piece of information comes from to work the problem..I know that I have initial Velocity (25.9) and In the Y- direction acceleration of -9.8m/s. Can someone please show me how to work out this problem and where the last piece of information is coming from?? A golfer imparts a speed of 25.9 m/s to a ball, and it travels the maximum possible distance before landing on the green. The tee and the green are at the same elevation. How much time does the ball spend in the air? What is the longest "hole in one" that the golfer can make, if the ball does not roll when it hits the green?Explanation / Answer
When the maximum distance is to be travelled, the ball must be hit so that it at an angle of 45 degrees.
This is the only information, I believe that you failed to get.
Anyways, solving further we get,
Horizontal component of speed = u cos (45)
Vertical component = u sin (45)
Now, applying equations of kinematics in this PROJECTILE motion problem, we have:
Along Y:
v = u - gt
0 = 25.9 sin (45) - 9.8(t)
t = 25.9 sin (45) / 9.8 = 1.8687 sec is required to reach the maximum height
Thus, time of flight = 2 * 1.8687 = 3.73 seconds is the time of flight. i.e the time, ball spends in air.
The horizontal distance = Range = u cos (45) * time of flight
Thus, maximum distance covered by ball = 25.9 * cos (45) * 3.73 = 68.45 m
thus, maximum of 68.45 m can be covered in one shot.
hope this helps. Please rate it ASAP. thanks
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