A very light rigid rod with a length of 1.32 m extends straight out from one end

Question

A very light rigid rod with a length of 1.32 m extends straight out from one end of a meter stick. The other end of the rod serves as a pivot and the system is set into oscillation.

Ip = ICM + MD2

(a) Determine the period of oscillation. [Suggestion: Use the parallel-axis theorem equation given above.  Where D is the distance from the center-of-mass axis to the parallel axis and M is the total mass of the object.]

_____________s

    (b) By what percentage does the period differ from the period of a simple pendulum 1.82 m long?

____________%

Explanation / Answer

the time period is

T = 2pi x (L/g)

where L is length of rod and g = 9.8 m/s^2

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