I also need help with 1 and 2. What is the tension in the Rope if the situation
ID: 2258091 • Letter: I
Question
I also need help with 1 and 2.
What is the tension in the Rope if the situation shown is in equilibrium? The mass of the Rod is 20kg, and it is 1.2m long. What are the horizontal and vertical forces on the joint holding the rod to the wall? You have the following static situation. Find the horizontal and vertical components of the force acting on the joint A. The long beam has a mass of 500kg and is 10m long. The rope X is attached at the center of the beam. An 80 cm long 1.5 mm diameter steel guitar string must be tightened to a tension of 1.5 kN. How much is the string stretched in the process?Explanation / Answer
1)
along x axis
Fx - T*cos45 =0 .....(1)
along y axis
Fy+T*sin45 = mg.....(2)
net torque = 0
T*sin45*L = m*g*1.....(3)
T = (m*g)/(sin45*1.2) = (20*9.8)/(sin45*1.2)
T = 230.988 N
from (1)
Fx = T*cos45 = 163.33 N
from (2)
Fy = m*g-T*sin45 = 32.67 N
F = sqrt(Fx^2+Fy^2)
2) along x axis
Fx-T = 0.....(1)
along y axis
Fy - M*g - m*g = 0........(2)
net torque =0
M*g*(L/2)*cos53 + m*g*L*cos53 = T*(L/2)*sin53.....(3)
500*9.8*5*cos53 + 200*9.8*cos53 = T*5*sin53
T = 63987.80 N..............
from (1)
Fx = T = 3987.80 N
from(2)
Fy = (M*g + m*g) = 6860 N
3) Y = F*L/(A*e)
e = F*L/A*Y = 1.5*1000*0.8)/(3.14*((0.75*10^-3)^2)*20*10^10)= 3.39 mm
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.