A battery of ? = 2.50 V and internal resistance R = 0.700 ? is driving a motor.

Question

A battery of ? = 2.50 V and internal resistance R = 0.700 ? is driving a motor. The motor is lifting a 2.0 N mass at constant speed v = 0.50                    m/s. Assuming no energy losses, find the current i in the circuit.                

1. Enter the lower current.                

                    2. Enter the higher current.                

                    3. Find the potential difference V across the terminals of the motor for the lower current.

                    4. Find the potential difference V across the terminals of the motor for the higher current.

Explanation / Answer

1.)when it is lifting upwards then P=0.5*2=1 W

so current

i=P/v(2.5-v/)0.7 v is potential across motor

v=0.32 V

I=3.11 A

2.)i=P/v=(2.5+v)/0.7

v=0.25 v

I=3.92 A

3.) potential difference V across the terminals of the motor for the lower current.

=2.4-0.32

=2.08 V

4.)potential difference V across the terminals of the motor for the higher current.

==2.15 V ans

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