please explain After performing an experiment concerning charging a capacitor Sa

Question

please explain

After performing an experiment concerning charging a capacitor Sally noticed that the potential difference across the capacitor reached 2/3 of its final value                    after 18 seconds.                 

                    A. Calculate the time constant for the resistor-capacitor combination                 

                    B. if the capacitance of the capicitor is 5 exp^-6 far ads , calculate the resistance of the resistor                 

                    C if the charging voltage is 15 volts , what is the current through the resistor at t = 15 sec                 

                    Please please explain thoroughly. Thanks so much

Explanation / Answer

A) vc = v0 ( 1 - e^(-t/tau))

2/3 = 1 - e^(-18/tau)

tau = 16.38 s

b) tau = RC

R = 16.38/5.0E-6=3.276E6 ohms

c) I = V/R e^(-t/tau) = 15/3.27E6*e^(-15/16.38)=1.84E-6 A

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