A particle with a mass of 1.45 kg is acted on by a force F x acting in the x -di

Question

A particle with a mass of 1.45 kg is acted on by a force Fx acting in the x-direction. If the magnitude of the force varies in time as shown in the figure below, determine the following.

A particle with a mass of 1.45 kg is acted on by a force Fx acting in the x-direction. If the magnitude of the force varies in time as shown in the figure below, determine the following. impulse of the force final velocity of the particle if it is initially at rest Find the final velocity of the particle if it is initially moving along the x-axis with a velocity of

Explanation / Answer

Hello

Force = change of momentum/time
change of momentum = Impulse = Force *time.
the impulse is the area under the curve = 24 N*s =24 N*m/s
24 Ns = m*v = 1.45*v
v = 8.275*2=16.55 m/s from rest
24 Ns = 1.45*v - (3*3)
1.45v = 33 Ns
v = 22.75m/s

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