As shown in the figure below, two blocks ( m 1 and m 2 ) are each released from
ID: 2259634 • Letter: A
Question
As shown in the figure below, two blocks (m1 and m2) are each released from rest at a height of
on a frictionless track and when they meet on the horizontal section of the track they undergo an elastic collision. If
and
determine the maximum heights to which they rise after the collision. Use the coordinate system shown in the figure.
Explanation / Answer
velocity of each point after reaching the bottom moost point.
V= sqrt (2*g*h) = srt(2*9.8*3.68) =8.493 m/s,
initial momentum, = 2.50 *8.493- 4.55*8.493 = -17.41
initial energy E = (2.5+4.55)*3.68*g = 254.51 J,
as collision is elastic, E and momentum must remain conserved,
let v1 and v2 be the velocity after colision,
final momentm= -17.41 = 2.55*vi1+4.55v2,
-17.41 = 2.55*v1+4.55v2
v1 = (-17.41-4.55v2) /2.55............(1)
final energy ,
254.51 = 1/2( 2.5v1^2 + 4.55 v2^2)..........
254.51= 1/2( 2.5{(-17.41-4.55v2) /2.55.}^2 + 4.55 v2^2)
solving these ,
v2 =1.91649 m/s,
v1 = -10.247 m/s
,
max height reached by the two blaocks,
h1 = v1^2/2g = 5.357 m
h2 = v2^2/2g = 0.1875m
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