An internal explosion breaks an object, initially at rest, into two pieces, one

Question

An internal explosion breaks an object, initially at rest, into two pieces, one of which has 1.4 times the mass of the other. If 7200J were released in the explosion, how much kinetic energy did each piece acquire? Express your answers using two significant figures. Enter your answers numerically separated by a comma. An internal explosion breaks an object, initially at rest, into two pieces, one of which has 1.4 times the mass of the other. An internal explosion breaks an object, initially at rest, into two pieces, one of which has 1.4 times the mass of the other. An internal explosion breaks an object, initially at rest, into two pieces, one of which has 1.4 times the mass of the other. If 7200J were released in the explosion, how much kinetic energy did each piece acquire? Express your answers using two significant figures. Enter your answers numerically separated by a comma. If 7200J were released in the explosion, how much kinetic energy did each piece acquire? Express your answers using two significant figures. Enter your answers numerically separated by a comma. If 7200J were released in the explosion, how much kinetic energy did each piece acquire? Express your answers using two significant figures. Enter your answers numerically separated by a comma.

Explanation / Answer

As initially the momenttum is zero,

momentum after collision must be 0,

let mass1 and mas2 have velocities , v1 and v2..

m1v1 = -m2v2,

v2 = m1/m2 * v1 = 1.4 v1..

wrtitng total energies ,

KE = 1/2*m1v1^2 + 1/2*m2*v2^2,

7200 = 0.5*m1*v1^2 + 0.5*m2*v2*v2

7200 = 0.5*m1*v1*v1 + 0.5*m2*v2*v2

7200 = 0.5*m2v2*v2/1.4 + 0.5*m2*v2*v2................(m2v2=m1v1)

7200 = KE2 / 1.4 +KE2,

KE2 = 4200 J,

similarly,

7200 = KE1 +KE1*1.4,

KE1 = 3000

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