Two infinite sheets of charge are separated by 10.0 cm as shown in the figure. S

Question

Two infinite sheets of charge are separated by 10.0cm  as shown in the figure. Sheet 1  has a surface charge distribution of ?1=2.05?C/m2  and sheet 2  has a surface charge distribution of ?2=-5.27?C/m2 .

Find the total electric field

a) at point P , 6.00cm  to the left of sheet 1

b) at point P? , 6.00cm  to the right of sheet 1 .

Please include a multiplication sign(*) to indicate that two units are being multiplied.

Two infinite sheets of charge are separated by 10.0cm as shown in the figure. Sheet 1 has a surface charge distribution of ?1=2.05?C/m2 and sheet 2 has a surface charge distribution of ?2=-5.27?C/m2 . Find the total electric field at point P , 6.00cm to the left of sheet 1 at point P? , 6.00cm to the right of sheet 1 .

Explanation / Answer

Here i'm denoting e for epsilon

For an infinite sheet, the field strength is independent of the distance and has magnitude
E = ?/2e0

Left of sheet 1, the field from sheet 1 points to the left and from sheet 2 points to the right :

E_x = (5.27 - 2.05)*10^-6 C/m^2 / (2 * 8.854 10^-12 F/m)

E_x(P) = 1.82 * 10^5 N/C (positive, so to the right)

For the second point P' (in between the sheets) we have

E_x(P') = (2.05 + 5.27)*10^-6 C/m^2 / (2e0)

E_x(P') = 4.14 * 10^5 N/C (positive, so to the right)

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