6. The murderer made it to the pier and was untying a boat, as the fearless poli
ID: 2260318 • Letter: 6
Question
6. The murderer made it to the pier and was untying a boat, as the fearless police detective was arriving at the shore-side of the pier. The detective struggled to unfasten his seat belt as the first of two ropes was untied. The killer dashed stepped out of the car. The pier was too long for the fighter of truth and justice to get to the villain in time. Greg knew that if the scoundrel could get away, he could elude capture for years, if not longer. There were too many islands in the area to be able to search them all. Also quite a few of the islands still had vestiges of war bunkers and recon towers. A smart man could hide for years, as long as he had food. The detective suspected that the killer had planned far enough in advance to have been able to store years worth of food somewhere. toward the second rope as the dauntless policeman So, faced with this dilemma, the hero of this tale, grabbed a shot-put sized metal ball, which just happened to be sitting near his end of the pier. He wound up ball flying in the air. As he released the ball, the bad guy made a critical error -he stopped and watched the ball coming in, mesmerized by the flight. for his cricket pitch and sent t he The ball was released 2.2 m above the wood planks on which the lawman was standing, the murderer was 1.650 m tall and was 25 m away, and the ball was released at angle of arccos(0.80000000) with the horizontal. At what speed does the ball need to be thrown to hit the villain on the top of his head?Explanation / Answer
Cos(theta) = 36.86 degree
time taken to travel vertical distance = 2.2 - 1.650 = 0.55 m
taking the Vertical component = VSin(theta)
horizontal componenet = V Cos(theta)
using equn of motion
Sy = u*t + 0.5 at^2
0.55 = VSin(theta)*t - 0.5*9.81*t^2
0.55 = VSin(36.86)*t - 0.5*9.81*t^2
0.55 = 0.6Vt - 4.905 t^2 -------------1
Sx = u*t + 0.5 at^2
25 = VCos(theta)*t
25 = VCos(36.86)*t
25 = 0.8Vt --------2
equating both equn
t = 3.85
V = 8.11 m/s
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