A car is traveling along a road, and the engine is turning over with an angular

Question

A car is traveling along a road, and the engine is turning over with an angular velocity of +220 rad/s. The driver steps on the accelerator, and in a time of 10.0 s the angular velocity increases to +300rad/s.

Sign Number Unit ? = ---Select---+- ---Select---rad/sm/s^2m/smrad/s^2rad A car is traveling along a road, and the engine is turning over with an angular velocity of +220 rad/s. The driver steps on the accelerator, and in a time of 10.0 s the angular velocity increases to +300rad/s. What would have been the angular displacement ? of the engine if its angular velocity had remained constant at the initial value of +220 rad/s during the 10.0 s? Include an explicit plus or minus sign along with your numerical answer. What would have been the angular displacement ? if the angular velocity had been equal to its final value of +300 rad/s during the 10.0 s? Include an explicit plus or minus sign along with your numerical answer. Determine the actual value of the angular displacement ? during this period. Include an explicit plus or minus sign along with your numerical answer.

Explanation / Answer

1) angular displacement would have been = angular velocity * time = +220 rad/s * 10 s = +2200 rad

2)angular displacement would have been = angular velocity * time = +300 rad/s * 10 s = +3000 rad

3) angular acceleration =( final angular velocity - initial angular velocity )/time = +(300 - 220 )/10 = 8 rad/s^2

we know that final angular velocity ^2 - inital angular velocity ^2 = 2* angular acceleration * angular displacement

300^2 - 220^2 = 2*8*S

41600 = 16 *S

angular displacement S=+ 2600 rad

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