An object, initially at rest, is pushed across a level, frictionless table by a

ID: 2261736 • Letter: A

Question

An object, initially at rest, is pushed across a level, frictionless table by a horizontal force FappObj for a time interval Dt. Sometime after the force has ceased its pushing, the object reaches the edge of the table and falls freely toward the floor below. After it has fallen a vertical distance d (but before it reaches the floor, the object explodes into two pieces, A (mass = mA) and B (mass = mB). Piece A An object, initially at rest, is pushed across a level, frictionless table by a horizontal force FappObj for a time interval Dt. Sometime after the force has ceased its pushing, the object reaches the edge of the table and falls freely toward the floor below. After it has fallen a vertical distance d (but before it reaches the floor, the object explodes into two pieces, A (mass = mA) and B (mass = mB). Piece A An object, initially at rest, is pushed across a level, frictionless table by a horizontal force FappObj for a time interval Dt. Sometime after the force has ceased its pushing, the object reaches the edge of the table and falls freely toward the floor below. After it has fallen a vertical distance d (but before it reaches the floor, the object explodes into two pieces, A (mass = mA) and B (mass = mB). Piece A An object, initially at rest, is pushed across a level, frictionless table by a horizontal force FappObj for a time interval Dt. Sometime after the force has ceased its pushing, the object reaches the edge of the table and falls freely toward the floor below. After it has fallen a vertical distance d (but before it reaches the floor, the object explodes into two pieces, A (mass = mA) and B (mass = mB). Piece A

Explanation / Answer

acceleration for Dt time = FappObj / (mA + mB)

velocity(Vx) after Dt time = FappObj*Dt / (mA + mB)

after fallen d distance

velocity in y direction due to gravity = - sqrt(2*g*d)

velocity in x direction = FappObj*Dt / (mA + mB)

after explosion

velocity of A in x direction = 0

velocity of B in x direction = [ (mA + mB)*FappObj*Dt / (mA + mB) ] / mB = FappObj*Dt / mB

after colliding with floor

velocity of B in x direction = FappObj*Dt / mB

velocity in y direction = 0

before coliding with object C

velocity of B in x direction = FappObj*Dt / mB since, floor is friction-less

velocity in y direction = 0

after colliding with object C

Velocity of combined mass B&C in x direction = [ mB*FappObj*Dt / mB ] / (mB + mC) by momentum conservation

= (FappObj*Dt) / (mB + mC)

velocity in y diection = 0

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An object, initially at rest, is pushed across a level, frictionless table by a

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