Please help. (Right-click the image and select view) As shown in the figure belo

Question

Please help. (Right-click the image and select view)

As shown in the figure below, cars #1 and #2 are sliding across a horizontal friction less surface. The cars are equipped with a coupling arrangement similar to the one on railroad cars. Car #1 overtakes car #2 and they have a totally in elastic collision and become coupled together. You know the mass of each car; m1 = 16.5 kg and m2 = 47.0 kg. In addition, you are provided with the following graph, which shows the momentum of car #1 before, during and after the collision. Determine the velocity of car #2 before the collision.

Explanation / Answer

For car 1

Before collision P = 100 = m*v = 16.5*v => v=6.06m/sec

After collision P =40 = 16.5*V => V = 2.4242 m/sec

Apply momentum conservation

16.5*6.06+47*V2 = (16.5+47)*2.4242 => V2 = velocity of car 2 before collision = 1.1478m/sec ANS

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