Three long, parallel conductors each carry a current of I = 1.60 A. The figure b
ID: 2262400 • Letter: T
Question
Three long, parallel conductors each carry a current of I = 1.60 A. The figure below is an end view of the conductors, with each current coming out of the page. Taking a = 0.70 cm, determine the magnitude and direction of the magnetic field at the following points.
(a) point A
magnitude 1 Three long, parallel conductors each carry a current of I = 1.60 degree A. The figure below is an end view of the conductors, with each current coming out of the page. Taking a = 0.70 cm, determine the magnitude and direction of the magnetic field at the following points.Explanation / Answer
a)
Ba =B1cos45 +B2cos45+B3
Ba =(uoI/2pia)[sqrt(2)*cos45 +(1/3)]
Ba =(4pi*10^-7*1.6/2pi*0.7*10^-2)*1.33
Ba =60.8 uT
Direction -towards bottom of the page
b)
Bb =B3 =uoI/2pi(2a) =uoI/4pia
Bb =(4pi*10^-7)*1.6/(4pi*0.7*10^-2)
Bb =22.86 uT
Direction towards bottom of the page
c)
Bc =0
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