Here is a screenshot of parts i and ii. Please help I missed 2 consective weeks
ID: 2262515 • Letter: H
Question
Here is a screenshot of parts i and ii. Please help I missed 2 consective weeks with illness and need help catching up!!! I do not need a whole lesson, just the work on how to solve.
An m1 = 8.0 kg box lies on a frictionless table, and is attached to a m2 = 5.0 kg box by a light cord passing over a rotating pulley. The pulley has a mass of 3.6 kg and a radius of 0.40 m. Just as the system is released, find: the linear acceleration of the masses the tension in the cord both above and below the pulley.Explanation / Answer
5)
let T is the tension in the string.
net force on m2, F2 = m2*g - T
m2*a = m2*g - T
==> T = m2*g - m2*a --(1)
net force on m1, F1 = T
m1*a = T --(2)
from equations 1 and 2
m1*a = m2*g - m2*a
==> a = m2*g/(m1+m2) = 3.77 m/s^2
T = m1*a = 8*3.77 = 30.15 N
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