Attached are two pics of the question Two identical bulbs (bulb 1 and bulb 2), a

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Attached are two pics of the question

Two identical bulbs (bulb 1 and bulb 2), a capacitor C, and a switch are connected to a battery as shown. The switch has been open for a long time. The battery is ideal and has a voltage of 4.0 volts Just after the switch is closed, rank the magnitudes of the four voltages Vbat, Vbuib i» Vbulb 2, and Vc. Explain your reasoning. After the switch has been closed for a long time, rank the magnitudes of the currents ibab ibulb 1 and ibulb 2- Explain your reasoning. (Assume that the battery is still fresh.) Just after the switch is opened, rank the magnitudes of the three currents ibat, ibulb l and i 2. Explain. Just after the switch is opened, how will the magnitude of the current through bulb 1 compare to the magnitude of the current through bulb 1 a long time after the switch was closed (in part B)? Explain.

Explanation / Answer

a)

Vbat = Vbulb1 = Vbulb2 > VC

just after the switch is closed, we can ignore the capacitor and voltage across battery, bulb 1 and bulb2 are will be equal because they are in parallel.

b)

Vbat = Vbulb1 = VC > Vbulb2

Afer a long tim, the capacitor will be charged and dont let the current to pass throgh the bulb 2. We can ignore bulb2 and therefore battery, bulb1 and the capacitor will be parallel and have a same voltage.

c)

ibulb1 = ibulb2 > ibat

After opening the swithch, no current pass through the battery (ibat=0).

d)

it is decreased

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