An object of mass 2 kg moving at v x = +1m/s is subjected to a single force F(x)

Question

An object of mass 2 kg moving at vx= +1m/s is subjected to a single force F(x) shown in the diagram below. What is its kinetic energy when it is at position x=4m?

Having trouble positing the diagram so I'll try and explain what I did up till now. I calculated the area under the curve from 0 to 4m. This would equal impulse or final momentum. Initial momentum is 2, and if i add that to the change in momentum, i should get final momentum which would allow me to get final speed which i could use to get kinetic energy. I keep getting the wrong answer so could someone let me know what's wrong with my process? Thanks

Explanation / Answer

initial KE = 0.5X2X1X1 = 1 J. Area under the curve gives the work done (if it is Force Vs Distance curve). Add this work done to initial KE to get final KE. ie. Final KE = 1J + Area under the F-x curve.

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