The figure ( Figure 1 ) shows a small plant near a thin lens. The ray shown is o

Question

The figure (Figure 1) shows a small plant near a thin lens. The ray shown is one of the principal rays for the lens. Each square is 1.00cm along the horizontal direction, but the vertical direction is not to the same scale. Use information from the diagram to answer the following questions.

A)What is the focal length of the lens?

B)Calculate where the image should be?

The figure (Figure 1) shows a small plant near a thin lens. The ray shown is one of the principal rays for the lens. Each square is 1.00cm along the horizontal direction, but the vertical direction is not to the same scale. Use information from the diagram to answer the following questions. What is the focal length of the lens? Calculate where the image should be?

Explanation / Answer

As the ray coming parallel to principal axis is converging after refraction , it means the lens is CONVEX LENS (CONVERGING LENS).

1) The focus for a lens is defined as the point where the rays coming parallel to principal axis meet/appears to meet the principal axis after refraction.

Here it is 4.00 cm away from the lens.

Thus focal length =4.00 cm

2) Applying the lens formula

1/(image distance) - 1/(object distance) = 1/(focal length)

with proper sign conventions

1/(image distance)=1/4 + 1/(-6)

1/(image distance) = 1/4 - 1/6

1/(image distance) = 2/24 = 1/12

image distance 12 cm away from the lens (at the right hand side of the lens).

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