In the figure above, the bottom wire carries a current of 4.1 A. The current of

Question

In the figure above, the bottom wire carries a current of 4.1 A. The current of the upper wire is directed in the opposite direction, and the total magnetic field at point p1 is zero.

What is the current in the top wire?

Given that the wires are separated by 2a, where a = 0.021 m, what is the magnitude of the magnetic field at point p2?

In the figure above, the bottom wire carries a current of 4.1 A. The current of the upper wire is directed in the opposite direction, and the total magnetic field at point p1 is zero. What is the current in the top wire? Given that the wires are separated by 2a, where a = 0.021 m, what is the magnitude of the magnetic field at point p2?

Explanation / Answer

field due to current carrying wire=(mu)*I/(4*pi*d)

so here 4.1/(3*a)=I/(a)

I=1.367 A

b)at P2,magnetic filed is into the page.

magnitude=2.6*10^(-5) T

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