1.You want to contrast a physical pendulum with a period of 4.0s at a location w

Question

1.You want to contrast a physical pendulum with a period of 4.0s at a location where g= 9.8s/s^2.

a.       What length of simple pendulum having this period

b.      Suppose the physical pendulum must be mounted in a case that is not more than 0.5m high. Can you devise a physical pendulum having a period of 4.0s s that will satisfy this requirement?

2. a block with mass M rests on a frictionless surface and is connected to a horizontal spring of force constant k. The other end of the spring is attached to a wall. A second block with mass m rests on top of the first block. The coefficient of static friction between the block is

Explanation / Answer

1. As we know that

T = 2pi*sqrt(L/g)

Therefore

4 = 2pi*sqrt(L/9.8)

L = 3.97 m

2. 0.5m height is not enough as we have length = 3.97 m

3.Here

Maximum Frictional Acceleration = usg

Acceleration due to oscillation = w^2A

= (k/(M+m))*A

By Equating both accelerations , we get

(k/(M+m))*A = usg

A = us(M+m)g/k

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