Consider a 10 cc syringe is connected to a 50 cc syringe. Information of the syr

Question

Consider a 10 cc syringe is connected to a 50 cc syringe. Information of the syringes are as follows: (mass of 10 cc piston) = 16 g (mass of 50 cc piston) = 60.6 g (diameter of 10 cc piston) = 14.7 mm (diameter of 50 cc piston) = 28.0 mm If a 50 g mass is placed on the 10 cc piston, what is the pressure exerted by the 10 cc piston onto the air underneath? I calculated this to be 3.811 kPa, but I can't seem to calculate the correct answer for the following question: ***If we repeated the above measurement by switching the pressure sensor to the 10 cc syringe and then placed the mass on top of the 50 cc piston, what would the pressure be (in kPa)?*** I would greatly appreciate any help!!

Explanation / Answer

P'=P2

F'/A=(3.8149*103)

F'=(pi*(28*10-3)2/4)*(3.8149*103)

F'=2.35 N

Force acting on the air by 50 cc piston is

F=mg=(60.6*10-3)*9.8=0.594 N

So force measure

dF=2.35-0.594=1.756 N

Related Questions

Navigate

• Browse (All)
• Browse C
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.