In an amusement park ride called The Roundup, passengers stand inside a 19.0 m -

Question

In an amusement park ride called The Roundup, passengers stand inside a 19.0m -diameter rotating ring. After the ring has acquired sufficient speed, it tilts into a vertical plane, as shown in the figur

a-Suppose the ring rotates once every 3.50s . If a rider's mass is 52.0kg , with how much force does the ring push on her at the top of the ride?

b-Suppose the ring rotates once every 3.50

s . If a rider's mass is 52.0kg , with how much force does the ring push on her at the bottom of the ride?

c-What is the longest rotation period of the wheel that will prevent the riders from falling off at the top?

In an amusement park ride called The Roundup, passengers stand inside a 19.0m -diameter rotating ring. After the ring has acquired sufficient speed, it tilts into a vertical plane, as shown in the figure

Explanation / Answer

w = 2Pi/3.5 = 1.795 rad/s

At the top of the ride, force = mrw^2 - mg

= 52(19/2 * 1.795^2 -9.8)

= 1082.08 N

(b) At bottom, F = mrw^2 +mg

= 52(19/2 * 1.795^2 +9.8)

= 2101.28 N

(c) If mrw^2 = mg, it prevents fall of riders.

w = sqrt(g/r) = 1.01566 rad/s

rotation period = 6.186 seconds

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.