The figure ( Figure 1 ) shows a model of a crane that may be mounted on a truck.

Question

The figure (Figure 1) shows a model of a crane that may be mounted on a truck.A rigid uniform horizontal bar of mass m1 = 80.00kg and length L = 5.000m is supported by two vertical massless strings. String A is attached at a distance d = 2.000m from the left end of the bar and is connected to the top plate. String B is attached to the left end of the bar and is connected to the floor. An object of mass m2 = 3000kg is supported by the crane at a distance x = 4.800m from the left end of the bar.

Throughout this problem, positive torque is counterclockwise and use 9.807m/s2 for the magnitude of the acceleration due to gravity.

Part A

Find TA, the tension in string A.

Part B

Find TB, the magnitude of the tension in string B.

The figure (Figure 1) shows a model of a crane that may be mounted on a truck.A rigid uniform horizontal bar of mass m1 = 80.00kg and length L = 5.000m is supported by two vertical massless strings. String A is attached at a distance d = 2.000m from the left end of the bar and is connected to the top plate. String B is attached to the left end of the bar and is connected to the floor. An object of mass m2 = 3000kg is supported by the crane at a distance x = 4.800m from the left end of the bar. Throughout this problem, positive torque is counterclockwise and use 9.807m/s2 for the magnitude of the acceleration due to gravity. Find TA, the tension in string A. Find TB, the magnitude of the tension in string B.

Explanation / Answer

Sum torque about string B
Ta*d-m1*g*L/2-m2*g*x=0
solve for Ta

Ta=g*(m1*L/2+m2*x)/d
plug in the numbers
Ta = 9.807*(80*5.0/2+3000*4.8)/2
Ta = 71591.1 N

for Tb, sum forces in the y
71591.1 - Tb - g*3000 = 0

Tb = 42170.1 N

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.