As the head of fulfillment for a small electronics factory, you are in charge of

Question

As the head of fulfillment for a small electronics factory, you are in charge of organizing the production schedule to fill orders. An order just came in for 1,525 radio consoles to be delivered in 5 weeks. Your assembly line can produce 9 consoles per hour. You put aside 15% of the consoles produced to build inventory for other orders, but the rest are used to fill this large order. Over the next five weeks, what is the fewest number of hours per week needed to produce enough radio consoles to fill this order?

Explanation / Answer

This is a logical question .

Let us start with given data :

Rate of Production (R)=9 consoles per hour .

Time =5 weeks

Order =1525 radio consoles.

Since it is given that 15% is stored for inventory.

Let us consider that total number of units produced in 5 weeks be 'x'

Hence , Units stored in inventory be 15% of x

=(15/100)*x

=0.15x units in inventory.

Now , remaining units are used to fulfil order that means

(100-15)% of x is used in fulfillment of order

=85% of x.

=0.85x

Since order = 1525 radio consoles .

Hence , solving :

0.85x =1525

We get , x= 1795 (approx)

Now , We need to produe 1795 units in 5 weeks for fullfillment of our order .

Since rate of production is 9 consoles per hour hence

1795 consoles can be produced in 1795/9 hours

=200 hours(approx)

This means it takes 200 hours to fulfill order in 5 weeks .

Hence , It will take 200/5 hours per week to fill this order

=40(approx) hours per week minimum is needed to produce enough radio console to fill this order.

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