I need help on probelms 10-14. I am having mixed thoughts about what the answers
ID: 2268468 • Letter: I
Question
I need help on probelms 10-14. I am having mixed thoughts about what the answers are and could really use a helping hand.
Thank you.
Explanation / Answer
10. The Connected load is 6945 VA.
(i) In Class Room - 12 fluorescent luminaries @85 VA
12 x 85 = 1020 VA.
AC - 5000 VA
(ii) In Corridor - 5 fluorescent luminaries @85 VA
5 x 85 = 425 VA
(iii) In Exterior - 4 Wall mounted luminaries @125 VA
4 x 125 = 500 VA.
Total = 6020 + 425 + 500 = 6945 VA
11. The Calculated Load is 8681.25 VA
(i) In Class Room
6020 VA x 125% = 6020 x (125/100) = 7525 VA
(ii) In Corridor
425 VA x 125% = 425 x (125/100) = 531.25 VA
(iii) In Exterior
500 VA x 125% = 500 x (125/100) = 625 VA
Total = 7525 + 531.25 + 625 = 8681.25 VA
13. Normally, when we connect load to the circuit, It draws Current. If it draws initially 100% amp in the circuit when connecting to circuit, there comes the real problem. Because for the continuous load operation, the load current will be constant. This current flows through terminals, conductors and overcurrent devices which in turn causes more heat build up.
Inorder to compensate the heat generated in the circuit. increasing the rating for overcurrent devices, ampacity of conductor for continuous operation of load by 125 %
14. Non-Coincident Loads
It is nothing but, two or more non coincident loads (larger load & lighter load) will be in use at the same time. For calculating the Feeder Demand, only the larger load can to be used only one time for calculation purpose.
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