2. Consider the Quadrature Encoder (ST) and EY block in the P&ID; in Figure 2. T
ID: 2268538 • Letter: 2
Question
2. Consider the Quadrature Encoder (ST) and EY block in the P&ID; in Figure 2. The Quadrature Encoder outputs two squarewave signals like the ones sketched here 5V oV time 5V oV -time The phase relationship of signals A and B determine the direction of rotation. If A leads B, then the motor shaft is rotating CCW If B leads A, then the motor shaft is rotating CW a. What is the phase difference between A and B in degrees? b. In what direction is the motor shaft rotating according to clock signals A and B given here? Explain. c. DB is a logic bit equal to O or 1 depending on the direction of shaft rotation: DB 0 motor rotating CCW motor rotating CW motor RPMs are negative motor RPMs are positive Given signals A and B are as shown above, will the direction bit DB be equal to 0 or 1?Explanation / Answer
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2a. When two waveforms are given, we have to see the common characteristics of both, do a mtaching, and then see which waveform has occurred first in time, from the matching. In the given waveform, it is evident that B leads A, because the positive pulse in B occurs first in time. Only later in time does A have its positive pulse. The phase difference is half of a time period (since the difference is one half of the positive pulse). This equals a phase difference of 90 degrees.
2b. Since B leads A, it rotates CW.
2c. Since the motor rotates CW, DB = 1.
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