(10 pts) A 0.20-mF capacitor discharges through a resistor with R capacitor to r
ID: 2268848 • Letter: #
Question
(10 pts) A 0.20-mF capacitor discharges through a resistor with R capacitor to reach 85% of its initial charge? ) 61 kS2. How long will it take for the 2) (10 pts) Use Kirchhoff's rules to solve for il (in A) in the 15.0 A, V = 14.0 V, and R circuit shown above where i 6.00 . Note that this drawing represents a subset of a full- circuit. ( 10 pts) In the circuit shown the capacitor is initially uncharged and the switch is open. Determine how much charge would accumulate after switch S has been closed for 0.1 ms. 3) R. 10 C 12 pF (10 pts) A simple RC circuit consists of a 1-uF capacitor in series with a 2800- resistor, a 6-V battery. and an open switch. Initially, the capacitor is uncharged. How long after the switch is closed will the voltage across the capacitor be 4.1 V? 4) ( 15 pts) A capacitor stores energy of 1.25 J. If when it is connected by means of a switch to a 15- resistor it discharges to half this value in 15 s. What is the initial voltage across the capacitor? 5) (15 pts) Two identical 2.5- resistors are parallel to each other, and the combination is in series with a 5.0-nF capacitor, in a circuit with a switch open. If initially 15.0 V is across the capacitor, how long after the switch is closed will the voltage across the resistor pair be 2.5 V? 6) 7) An RC circuit consists of a resistor with resistance 1.0 k2, a 120-V battery, and two capacitors, Ci and C2, with capacitances of 20.0 F and 600 F, respectively. The capacitors are connected in parallel to each other. Initially, the capacitors are uncharged; and the switch is closed at 0 s. a) (10 pts) What is the current through the resistor a long time after the switch is closed? b) How much charge will be stored in each capacitor after a long time has elapsed? (10 pts) CL C, (10 pts) C2Explanation / Answer
1)Given,
C = 0.2 mF ; R = 61 k Ohm
we know that
Q = Q0 (1 - e^-t/RC)
0.85 Q0 = Q0 (1 - e^-t/RC)
e^-t/RC = 1-0.85 = 0.15
taking natural long both sides
-t/Rc = -1.897
t = 1.897 x RC = 1.897 x 61 x 10^3 x 0.2 x 10^-3 = 23.14 s
Hence, t = 23.14 s
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