5. Now let us consider the heat lost to breathing for the person in number 4. Th

Question

5. Now let us consider the heat lost to breathing for the person in number 4. They are taking 1 L breaths at a rate of 211 breaths per hour. The air they breathe in is dry and at a temperature of -10°C. The air they exhale is saturated with water and has risen to a temperature of 15°C. How much heat do they lose each hour to breathing? The partial pressure of water is 24 Torr when the air is saturated, and it takes 6.98 x 103 Cal to raise 1 mole of air by 1°C under the conditions of this problem. Assume air is an ideal gas at standard temperature and pressure to work out the number of moles of air being warmed. a. 1.68 Cal/hr b. 2.19 Cal/hr c. 4.75 Cal/hr d. 5.69 Cal/hr e. 7.13 Cal/hr Say that you are standing in front of the speakers at a concert. The sound wave from the speakers enters your body from air in a direction that is perpendicular to the surface of your chest. Once inside your chest, the sound waves enter your heart in a direction that is perpendicular to the surface of t energy would pass into your heart during a 2 hour show? Assume that the area of the heart intercepting the sound waves is 30 cm2 and that the 'loudness' of the show is 100 dB where you are standing. The speed of sound in the tissue of your chest, between the chest wall and the heart, is 1.613 X 105 cm/s. The speed of sound in your heart tissue is 1.576 X 105 cm/s. The density of the tissue of your chest is 1.120 g/cm3. The density of the tissue of your heart is 1.060 6. cm a. 5.87 X 104J b. 9.14 X 104J c. 1.33 X 104J d. 2.03 X 10-4J e. 6.07 X 104J

Explanation / Answer

5. Here, delta T= 15- (-10)= 25C

Assume normal person state breathe in a volume 1L at a rate of 211 Breathe/hr

So heat loss = Q= m x c x deltaT = 6.98x10^-3 x24 x 25 = 4.7Cal/hr So, the option C is correct.

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