Verizon LTE 12:37 PM @flipitphysics.com A racquet ball with mass m . 0.243 kg is

Question

Verizon LTE 12:37 PM @flipitphysics.com A racquet ball with mass m . 0.243 kg is moving toward the wall at v 14.6 m/s and at an angle of -26, with respect to the horizontal. The ball makes a perfectly elastic collision with the solid, frictionless wall and rebounds at the same angle with respect to the horizontal. The ball is in contact with the Wal for t = 0.066 s. What is the magnitude of the initial momentum of the racquet ball m/s What is the magnitude of the change in momentum of the racquet ball? kg-m/s What is the magnitude of the average force the wall exerts on the racquet ball? Now the racquet ball is moving straight toward the wall at a velocity of v -14.6 m/sThe ball makes an inelastic collision with the solid wall and leaves the wall in the opposite direction at v -8.8 m/s. The ball exerts the same average force on the ball as before. What is the magnitude of the change in momentum of the racquet ball? kg-m/ssn 5What is the time the ball is in contact with the wall? What is the change in kinetic energy of the racquet ball?

Explanation / Answer

here,

mass , m = 0.243 kg

initial speed , u = - 14.6 m/s

a)

the magnitude of the initial momentum , Pi = m * u = 3.57 kg.m/s

b)

the magnitude of final momentum , Pf = m * v = 3.57 kg.m/s

c)

change in momentum , dP = (Pf - Pi) * cos(theta)

dP = ( 3.57 - ( 3.57)) * cos(26) = 6.38 kg.m/s

the magnitude of average force , F = dP /t

F = 96.6 N

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