In this problem, you will explore how phenotypic variance is comprised of both g

ID: 226933 • Letter: I

Question

In this problem, you will explore how phenotypic variance is comprised of both genetic variance and environmental variance.

Part A

Consider two pure-breeding lines of grapes, P1 and P2.

The average diameter of P1grapes is 1.2 cm and the variance is 0.30 cm2.

The average diameter of P2grapes is 1.6 cm and the variance is 0.56 cm2.

The two pure-breeding lines are crossed to produce F1progeny.

Based on this description, which of the following statements is false?

A. VG for P1 = 0

B. VE for F1 is > 0 C. VP for P1 < VG for P2 D.VG for P2 = 0 E. VG for F1 is > 0

VP = VG + VE

where VE is the environmental variance and can be calculated by averaging variances from the two parental generations:
(0.30 + 0.56)/2 = 0.43

We then take this result and average the variance from the F1 generation to determine the VE:

VE = (0.43 + 0.40)/2 = 0.42

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