Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

%3Cdiv%20style%3D%22line-height%3A%26nbsp%3B21px%3B%26nbsp%3Bcolor%3A%26nbsp%3Br

ID: 2269492 • Letter: #

Question

%3Cdiv%20style%3D%22line-height%3A%26nbsp%3B21px%3B%26nbsp%3Bcolor%3A%26nbsp%3Brgb(68%2C%26nbsp%3B68%2C%26nbsp%3B68)%3B%26nbsp%3Bfont-family%3A%26nbsp%3BCalibri%2C%26nbsp%3Bsans-serif%3B%26nbsp%3Bfont-size%3A%26nbsp%3B15px%3B%22%3EYou%26nbsp%3Bhave%26nbsp%3Ban%26nbsp%3Belectron%26nbsp%3Bgun%2C%26nbsp%3Bin%26nbsp%3Bwhich%26nbsp%3Belectrons%26nbsp%3Btravel%26nbsp%3Bthrough.%26nbsp%3BFind%26nbsp%3Bout%26nbsp%3Bhow%26nbsp%3Blong%26nbsp%3Bit%26nbsp%3Bwill%26nbsp%3Btake%26nbsp%3Bfor%26nbsp%3Belectrons%26nbsp%3B%3C%2Fdiv%3E%3Cdiv%26nbsp%3Bstyle%3D%22line-height%3A%26nbsp%3B21px%3B%26nbsp%3Bcolor%3A%26nbsp%3Brgb(68%2C%26nbsp%3B68%2C%26nbsp%3B68)%3B%26nbsp%3Bfont-family%3A%26nbsp%3BCalibri%2C%26nbsp%3Bsans-serif%3B%26nbsp%3Bfont-size%3A%26nbsp%3B15px%3B%22%3E%26nbsp%3Bto%26nbsp%3Btravel%26nbsp%3Bthrough%26nbsp%3Bthe%26nbsp%3Belectron%26nbsp%3Bgun.%26nbsp%3BThe%26nbsp%3Bdistance%26nbsp%3Bbetween%26nbsp%3Ba%26nbsp%3Bcharge%26nbsp%3BA%26nbsp%3Band%26nbsp%3BB%26nbsp%3Bof%26nbsp%3Bthe%26nbsp%3Bcannon%26nbsp%3Bis%26nbsp%3B6%26nbsp%3Bcm%26nbsp%3Band%26nbsp%3Bthe%26nbsp%3Bvoltage%26nbsp%3Bbetween%26nbsp%3Bthe%26nbsp%3Bcharges%26nbsp%3Bis%26nbsp%3B360%26nbsp%3BV.%26nbsp%3BThe%26nbsp%3Bvoltage%26nbsp%3Bis%26nbsp%3Bdivided%26nbsp%3Bin%26nbsp%3Bhalf%26nbsp%3Bat%26nbsp%3Beach%26nbsp%3Bcharge.%26nbsp%3BHow%26nbsp%3Bcan%26nbsp%3Bi%26nbsp%3Bcalculate%26nbsp%3Bthe%26nbsp%3Btime%3F%26nbsp%3BWhat%26nbsp%3BVoltage%26nbsp%3Bshould%26nbsp%3Bi%26nbsp%3Buse%3F%3C%2Fdiv%3E

Explanation / Answer

Electric field = V/d = 360/0.06 = 6000 N/C

Force = E*e

Acc, a = E*e/m , e and m for electrone

Time = sqrt(2d/a) = 1*10^-8 sec