The drawings show three charges that have the same magnitude but may have differ

Question

The drawings show three charges that have the same magnitude but may have different signs. In all cases the distance d between the charges is the same. The magnitude of the charges is |q|= 6.4 ?C, and the distance between them is d = 0.8 mm. Determine the magnitude of the net force on charge 2 for each of the three drawings.

a. F =

b. F = 0

c. F =

The drawings show three charges that have the same magnitude but may have different signs. In all cases the distance d between the charges is the same. The magnitude of the charges is |q|= 6.4 ?C, and the distance between them is d = 0.8 mm. Determine the magnitude of the net force on charge 2 for each of the three drawings. F = F = 0 F =

Explanation / Answer

here F=Kq1q2/r^2

so,

a)

Force on q2 due to q1 = 9*10^9 * (6.4*10^6 *6.4*10^6)/(0.8*10^-3)^2 = 576000 N leftside

similarly,

Force on q2 due to q3 = 9*10^9 * (6.4*10^6 *6.4*10^6)/(0.8*10^-3)^2 = 576000 N leftside

so,

resultant force = 576000 * 2 = 1152000 N

b)

Force on q2 due to q1 = 9*10^9 * (6.4*10^6 *6.4*10^6)/(0.8*10^-3)^2 = 576000 N rightside

similarly,

Force on q2 due to q3 = 9*10^9 * (6.4*10^6 *6.4*10^6)/(0.8*10^-3)^2 = 576000 N leftside

so,

resultant force = 576000 - 576000 =0 N

c)

Force on q2 due to q1 = 9*10^9 * (6.4*10^6 *6.4*10^6)/(0.8*10^-3)^2 = 576000 N leftside

similarly,

Force on q2 due to q3 = 9*10^9 * (6.4*10^6 *6.4*10^6)/(0.8*10^-3)^2 = 576000 N downward

so,

resultant force = sqrt(576000^2 + 576000^2) =814587.09 N

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