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Question Part Points Submissions Used The electric field outside any spherically

ID: 2269840 • Letter: Q

Question


Question Part Points Submissions Used The electric field outside any spherically symmetric charge distribution is the same as if all of the charge were concentrated into a point charge. Gauss's law can be used to show the electric field inside a spherically symmetric charge distribution is zero if none of the charge is at a distance from the center less than that of the point where we determine the field.

Using the above information, we can find the electric field at any radius for any spherically symmetrical charge distribution. A solid sphere of charge of radius R has a total charge of q uniformly spread throughout the sphere. (a) Find the magnitude of the electric field for R ? r. (Use any variable or symbol stated above along with the following as necessary: k for the Coulomb constant.)
E(R ? r) =
(b) Find the magnitude of the electric field for r ? R. (Use any variable or symbol stated above along with the following as necessary: k for the Coulomb constant.)
E(r ? R) =
(c) Sketch a graph of E(r) for 0 ? r ? 3R. (Do this on paper. Your instructor may ask you to turn in this work.)
Question Part Points Submissions Used
Question Part Points Submissions Used
Question Part Points Submissions Used
Question Part Points Submissions Used
Question Part Points Submissions Used The electric field outside any spherically symmetric charge distribution is the same as if all of the charge were concentrated into a point charge. Gauss's law can be used to show the electric field inside a spherically symmetric charge distribution is zero if none of the charge is at a distance from the center less than that of the point where we determine the field.

Using the above information, we can find the electric field at any radius for any spherically symmetrical charge distribution. A solid sphere of charge of radius R has a total charge of q uniformly spread throughout the sphere. (a) Find the magnitude of the electric field for R ? r. (Use any variable or symbol stated above along with the following as necessary: k for the Coulomb constant.)
E(R ? r) =
(b) Find the magnitude of the electric field for r ? R. (Use any variable or symbol stated above along with the following as necessary: k for the Coulomb constant.)
E(r ? R) =
(c) Sketch a graph of E(r) for 0 ? r ? 3R. (Do this on paper. Your instructor may ask you to turn in this work.) The electric field outside any spherically symmetric charge distribution is the same as if all of the charge were concentrated into a point charge. Gauss's law can be used to show the electric field inside a spherically symmetric charge distribution is zero if none of the charge is at a distance from the center less than that of the point where we determine the field.

Using the above information, we can find the electric field at any radius for any spherically symmetrical charge distribution. A solid sphere of charge of radius R has a total charge of q uniformly spread throughout the sphere. (a) Find the magnitude of the electric field for R ? r. (Use any variable or symbol stated above along with the following as necessary: k for the Coulomb constant.)
E(R ? r) =
(b) Find the magnitude of the electric field for r ? R. (Use any variable or symbol stated above along with the following as necessary: k for the Coulomb constant.)
E(r ? R) =
(c) Sketch a graph of E(r) for 0 ? r ? 3R. (Do this on paper. Your instructor may ask you to turn in this work.) (a) Find the magnitude of the electric field for R ? r. (Use any variable or symbol stated above along with the following as necessary: k for the Coulomb constant.)
E(R ? r) =
(b) Find the magnitude of the electric field for r ? R. (Use any variable or symbol stated above along with the following as necessary: k for the Coulomb constant.)
E(r ? R) =
(c) Sketch a graph of E(r) for 0 ? r ? 3R. (Do this on paper. Your instructor may ask you to turn in this work.) Question Part Points Submissions Used

Explanation / Answer

a) E = k*q/r^2


b) E = [k*q/R^2]*(1 - r/R)


c) The graph curves upward from 3R to R, then follows a straight line to zero from r = R to r = 0.



This is the same relationship as the gravitational field of a solid sphere.

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