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I\'ve been trying to research other questions similar, I can\'t figure it out. P

ID: 2270342 • Letter: I

Question

I've been trying to research other questions similar, I can't figure it out. PLEASE help me. Thanks.


Three charges are arranged as shown in the figure below. Find the magnitude and direction of the electrostatic force on the charge q = 4.96 nC at the origin. (Let r12 = 0.290 m.)     

magnitude                                    
Use Coulomb's law to find the force that each charge exerts on the charge at the origin and combine the forces to find the net force. N direction          Three charges are arranged as shown in the figure below. Find the magnitude and direction of the electrostatic force on the charge q = 4.96 nC at the origin. (Let r12 = 0.290 m.)

Explanation / Answer

force due to 6 nc charge = k*6*10^(-9)*4.96*10^(-9) / (0.29)^2 to the left


force due to -3 nc charge = k*3*10^(-9)*4.96*10^(-9) / (0.1)^2 downward


so the resultant force = sqrt [(k*6*10^(-9)*4.96*10^(-9) / (0.29)^2)^2 + (k*3*10^(-9)*4.96*10^(-9) / (0.1)^2)^2]

=13.746 * 10^(-6)Nbbc2e


direction =180 + (arc tan (k*3*10^(-9)*4.96*10^(-9) / (0.1)^2 /k*6*10^(-9)*4.96*10^(-9) / (0.29)^2)

= 180 + 26.56

= 206.56 degrees

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