I\'ve been trying to research other questions similar, I can\'t figure it out. P
ID: 2270342 • Letter: I
Question
I've been trying to research other questions similar, I can't figure it out. PLEASE help me. Thanks.
Three charges are arranged as shown in the figure below. Find the magnitude and direction of the electrostatic force on the charge q = 4.96 nC at the origin. (Let r12 = 0.290 m.)
magnitudeUse Coulomb's law to find the force that each charge exerts on the charge at the origin and combine the forces to find the net force. N direction Three charges are arranged as shown in the figure below. Find the magnitude and direction of the electrostatic force on the charge q = 4.96 nC at the origin. (Let r12 = 0.290 m.)
Explanation / Answer
force due to 6 nc charge = k*6*10^(-9)*4.96*10^(-9) / (0.29)^2 to the left
force due to -3 nc charge = k*3*10^(-9)*4.96*10^(-9) / (0.1)^2 downward
so the resultant force = sqrt [(k*6*10^(-9)*4.96*10^(-9) / (0.29)^2)^2 + (k*3*10^(-9)*4.96*10^(-9) / (0.1)^2)^2]
=13.746 * 10^(-6)Nbbc2e
direction =180 + (arc tan (k*3*10^(-9)*4.96*10^(-9) / (0.1)^2 /k*6*10^(-9)*4.96*10^(-9) / (0.29)^2)
= 180 + 26.56
= 206.56 degrees
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