2). a). Which food source carries the highest energy content per weight? I). pro
ID: 227081 • Letter: 2
Question
2).
a). Which food source carries the highest energy content per weight?
I). protein
II). carbohydrates
III). vitamins
IV). fats
b). Raw sugar and honey have fewer calories than table sugar
True
False
c). A food has 5 g of protein, 5 g of carbohydrate and 1 g of fat. What is the calorie distribution?
I). 1% fat, 5 % protein, 5% carbohydrate
II). 40% fat, 40% protein, 20% carbohydrate
III). 20% fat, 40 % protein, 40% carbohydrate
IV). 10% fat, 45% protein, 45% carbohydrate
d). What is the sbustrate of the catalase enzymatic reaction used in our Biology 121 lab?
I). potato
II). catalase
III). oxygen
IV). hydrogen peroxide
e). Why would very high temperatures disrupt an enzymatic reaction?
I). Enzyme is moving too fast
II). Enzyme is denatured
III). Substrate is disappearing
IV). product is reversing
Explanation / Answer
a). Which food source carries the highest energy content per weight?
I). protein
II). carbohydrates
III). vitamins
IV). Fats---------answer
explanation
Carbohydrate
17kJ (4 kcal) per gram
Protein
17kJ (4 kcal) per gram
Fat
37kJ (9 kcal) per gram
Alcohol
29kJ (7 kcal) per gram
b). Raw sugar and honey have fewer calories than table sugar
True
False----------answer
Raw sugar --teaspoon ----16 calories
tablespoon of honey ----------- 64 calories
================================================================
c). A food has 5 g of protein, 5 g of carbohydrate and 1 g of fat. What is the calorie distribution?
I). 1% fat, 5 % protein, 5% carbohydrate
II). 40% fat, 40% protein, 20% carbohydrate
III). 20% fat, 40 % protein, 40% carbohydrate--------------answer
IV). 10% fat, 45% protein, 45% carbohydrate
5g carbohydrate x 4 kcal/g = 20kcal
5g protein x 4 kcal/g = 20 kcal
1g fat x 9kcal/g = 9 kcal
Total = 49 kcal
(9/49)*100=18.36%----fat
(20/49)*100=40.81%----fat
(20/49)*100=40.81%----fat
d). What is the sbustrate of the catalase enzymatic reaction used in our Biology 121 lab?
I). potato-answer
II). catalase
III). oxygen
IV). hydrogen peroxide
e). Why would very high temperatures disrupt an enzymatic reaction?
I). Enzyme is moving too fast
II). Enzyme is denatured-----------answer
III). Substrate is disappearing
IV). product is reversing
Change the pH and the nzyme stops working. enhancing the temperature to 60°C will make a lasting change the state of the active sites of enzymes. This is the reason compounds quit working when they are warmed. We say they have moved toward becoming denature
Carbohydrate
17kJ (4 kcal) per gram
Protein
17kJ (4 kcal) per gram
Fat
37kJ (9 kcal) per gram
Alcohol
29kJ (7 kcal) per gram
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