1) Using the number density of gas at sea level of 2.55*10^25 m^-3 and the radiu

Question

1) Using the number density of gas at sea level of 2.55*10^25 m^-3 and the radius of the molecule s*10^-10 m to show that quantitativly, the gas is mostly empty space.

2) Assuming an atmosphere of constant temperature and comosition, and a scaleheight of 8km, what would these 2 densities (mass and number density) decrease to at an altitude of low earth orbit (250 km)?

3) More realiztically, the pressure at low earth orbit is 10^-7 mbars, the composition is atmoic oxygen and the temp is 370 K. What is a more realistic value of n? Calculate n for this realistic pressure

Explanation / Answer

1)m=d*v

v=4pir^3/3=1.3*10^-30

m=3.315*10^-5 kg

which is negligible

the gas is mostly empty space.

2)mass doent chamge with altitude

density changes as d=do(1-r/R)

d=2.464*10^25

3)PV=nRT

n=PV/RT

V=22.4litres

n=7.28*10^-10

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