A string connects the two-body system, which is defined as the cart and force pr
ID: 2271416 • Letter: A
Question
A string connects the two-body system, which is defined as the cart and force probe together (m1) and the falling mass (
m2). The cart and force probe are held in place initially; when released, m2accelerates downward and the cart and force probe accelerate along the track to the right. The force probe first measures the tension in the string at rest and then as it accelerates.
http://session.masteringphysics.com/problemAsset/1000228940/30/hangingmass.jpg
what is the difference between the tension when m1 is held at rest (Trest) and the tension when the system is accelerating (
T). Express your answer in terms of any or all of m1, m2, and g:
Trest- T=?
Typical values for m1 and m2 are on the order of 750 g and 50 g, respectively. Calculate the value of the acceleration in units of g for these values of mass.
a= ? units of g
Calculate the magnitude of the percentage drop in Trest when the system accelerates, for m1 and m2 of 1000 g and 100 g.
??Trest?T??T ?= ?
Before release, what if the system was held at rest by fixing m2 in place instead of fixing m1 in place: what would be the tension in the string?
Trest = ?
Trest- T=?
Typical values for m1 and m2 are on the order of 750 g and 50 g, respectively. Calculate the value of the acceleration in units of g for these values of mass.
a= ? units of g
Calculate the magnitude of the percentage drop in Trest when the system accelerates, for m1 and m2 of 1000 g and 100 g.
??Trest?T??T ?= ?
Before release, what if the system was held at rest by fixing m2 in place instead of fixing m1 in place: what would be the tension in the string?
Trest = ?
Explanation / Answer
Trest =m2g.
T= m1a. where a= accelaration of system = m2g/(m+m2).
so T= m1*m2g/(m1+m2)
1) m= 750 ,m2= 50
Trest= 50g
T= 46.875g
2) m= 1000 ,m2= 100
Trest= 100g
T = 90.90g
(Trest - T)/T= (100 -90.90) /100 =0.091
3) Then Tresst would be Zero .
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