On the Apollo 14 mission to the moon, astronaut Alan Shepard hit a golf ball wit

Question

On the Apollo 14 mission to the moon, astronaut Alan Shepard hit a golf ball with a golf club improvised from a tool. The free fall acceleration on the moon is 1/6 of its value on earth. Suppose he hit the ball with a speed of 22 m/s at an angle 29 degrees above the horizontal.

PLEASE ANSWER ALL QUESTIONS THANK YOU!!!!!!!!

A) How long was the ball flight? (answer should be in seconds)

B) How far did it travel? (answer should be in meters)

C) Ignoring air resistance, how much farther would it travel on the moon than on earth? (answer should be in meters)

Explanation / Answer

A)t=2*22*sin(29 degree)/(1/6*9.8)=13.060

B)distance=13.06*22*cos(29 degree)=251.3m

C)on earth time=2*22*sin(29 degree)/(9.8)=2.1766

distance=2.1766*22*cos(29 degree)=41.75m

so difference=251.29-41.75=209.54

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