A C 1 = 2.60 ? F capacitor is charged to 855 V and a C 2 = 7.20 ? F capacitor is
ID: 2272180 • Letter: A
Question
A C1 = 2.60?F capacitor is charged to 855V and a C2 = 7.20?F capacitor is charged to 661V . These capacitors are then disconnected from their batteries. Next the positive plates are connected to each other and the negative plates are connected to each other. Part A What will be the potential difference across each? [Hint: charge is conserved.] Enter your answers numerically separated by a comma. V1, V2 = V Part B What will be the charge on each? Enter your answers numerically separated by a comma. Q1, Q2 = C A C1 = 2.60?F capacitor is charged to 855V and a C2 = 7.20?F capacitor is charged to 661V . These capacitors are then disconnected from their batteries. Next the positive plates are connected to each other and the negative plates are connected to each other. A C1 = 2.60?F capacitor is charged to 855V and a C2 = 7.20?F capacitor is charged to 661V . These capacitors are then disconnected from their batteries. Next the positive plates are connected to each other and the negative plates are connected to each other. A C1 = 2.60?F capacitor is charged to 855V and a C2 = 7.20?F capacitor is charged to 661V . These capacitors are then disconnected from their batteries. Next the positive plates are connected to each other and the negative plates are connected to each other. Part A What will be the potential difference across each? [Hint: charge is conserved.] Enter your answers numerically separated by a comma. V1, V2 = V Part B What will be the charge on each? Enter your answers numerically separated by a comma. Q1, Q2 = C Part A What will be the potential difference across each? [Hint: charge is conserved.] Enter your answers numerically separated by a comma. V1, V2 = V Part A What will be the potential difference across each? [Hint: charge is conserved.] Enter your answers numerically separated by a comma. V1, V2 = V Part B What will be the charge on each? Enter your answers numerically separated by a comma. Q1, Q2 = C Part B What will be the charge on each? Enter your answers numerically separated by a comma. Q1, Q2 = CExplanation / Answer
Charge on C1
Q1=C1V1 =2.6*10^-6*855
Q1=2.223*10^-3 C
Charge on C2
Q2=C2V2=7.2*10^-6*661
Q2=4.76*10^-3 C
equivalent capacitance
C=C1+C2=2.6+7.2
C=9.8 uF
Total charge
Q=Q1+Q2 =2.223*10^-3+4.76*10^-3
Q=6.983*10^-3 C
a)
V1'=V2'=Q/C =6.983*10^-3/9.8*10^-6
V1'=V2'=712.55 V
b)
Q1'=C1V1'=2.6*10^-6*712.55
Q1' =1.85*10^-3 C or 1.85 mC
Q2'=C2V2' =7.2*10^-6*712.55
Q2'=5.13*10^-3 C or 5.13 mC
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