1) 2) 3) A third point charge q 3 = 2.4 ?C is now positioned along the y-axis at
ID: 2272257 • Letter: 1
Question
1)
2)
3)
A third point charge q3 = 2.4 ?C is now positioned along the y-axis at a distance d = 8 cm from q1 as shown. What is Ex(P), the x-component of the field produced by all 3 charges at point P?
4)
5)
Two point charges (q1 = -4.7?C and q2 = 8.4 ?C) are fixed along the x-axis, separated by a distance d = 8 cm. Point P is located at (x,y) = (d,d). What is Ex(P), the value of the x-component of the electric field produced by q1 and q2 at point P? What is Ey(P), the value of the y-component of the electric field produced by q1 and q2 at point P? A third point charge q3 = 2.4 ?C is now positioned along the y-axis at a distance d = 8 cm from q1 as shown. What is Ex(P), the x-component of the field produced by all 3 charges at point P? Suppose all charges are now doubled (i.e., q1 = -9.4 ?C, q2 = 16.8 ?C, q3 = 4.8 ?C), how will the electric field at P change? How would you change q1 (keeping q2 and q3 fixed) in order to make the electric field at point P equal to zero?Explanation / Answer
E1 = k*q1/(2*d^2) = 9*10^9*4.7*10^-6/(2*0.08^2) = 3.304*10^6 N/c
E1x = -E*cos(45) = -2.337*10^6 N/c
E1y = -E*sin(45) = -2.337*10^6 N/c
E2 = k*q2/(d^2) = 9*10^9*8.4*10^-6/(0.08^2) = 11.8*10^6 N/c
E2x = 0
E2y = 11.8*10^6 N/c
1) Ex = E1x + E2x = -2.337*10^6 N/c
2) Ey = E1y + E2y = 9.463*10^6 N/c
3)
E3 = k*q3/(d^2) = 9*10^9*2.4*10^-6/(0.08^2) = 3.375*10^6 N/c
E3x = 3.375*10^6 N/c
E3y = 0
Ex = E1x + E2x + E3x = 1.038*10^6 N/c
4) Its magnitude will double and its direction will remain the same
5) Increase its magnitude and keep its sign the same
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.