A uniformly charged insulating rod of length 12.0 cm is bent into the shape of a

Question

A uniformly charged insulating rod of length 12.0 cm is bent into the shape of a semicircle as shown in the figure below. The rod has a total charge of ?7.50

A uniformly charged insulating rod of length 12.0 cm is bent into the shape of a semicircle as shown in the figure below. The rod has a total charge of ?7.50 mu C. Find the magnitude of the electric field at O, the center of the semicircle. Find the direction of the electric field at O, the center of the semicircle. to the leftto the right upwarddownwardinto the pageout of the page

Explanation / Answer

ELECTRIC FIELD DUE TO SEMICIRCUALR CHARGE AT THE AXIS=2KQ/PIE R^2

K=9*10^9=1/4PIE EPSILON

=2*9*10^9*-7.5 *10^-6/3.142 *(12*10^-2)^2

=2.98*10^6 N/C

DIRECTION IS NEGATIVE X DIRECTION [KEEP POSITIVE TEST CHARGE AT AXIS,ALL PATRS OF RING WILL ATTRACT IT TOWARDS LEFT,ON TAKING THEIR COMPONENTS,Y COMPONENT BECOMES 0 AND NET DIRECTION IS NEGATIVE X]

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