Julie throws a ball to her friend Sarah. The ball leaves Julie\'s hand a distanc

Question

Julie throws a ball to her friend Sarah. The ball leaves Julie's hand a distance 1.5 meters above the ground with an initial speed of 14 m/s at an angle 58 degrees with respect to the horizontal. Sarah catches the ball 1.5 meters above the ground.

the distance between the two girls is 17.95 m

After catching the ball, Sarah throws it back to Julie. The ball leaves Sarah's hand a distance 1.5 meters above the ground.  It is moving with a speed of 10 m/s when it reaches a maximum height of 11 m above the ground.

How high above the ground will the ball be when it gets to Julie?

Explanation / Answer

so vx = 10 m/s

now find vy

vy^2 = v0y^2 + 2 a dy

0 = v^2 -2*9.81*(11-1.5)

vy = 13.65 m/s

now x direction

17.95 = 10*t

t= 1.795

now y direction

y = 1.5 + 13.65*1.795-0.5*9.81*1.795^2= 10.2 m

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