Here are the two questions. Please answer! The magnetic filed at the surface oft

Question

Here are the two questions. Please answer!

The magnetic filed at the surface ofthe Earth varies a bit, but suppose where you are it happens to be 0.45 micro tesla in magnitude and pointing due north. If you throw a steel ball 866.2 Coulombs of change on it {v} m/s due East, how many Newtons of force will the magnetic force exert on it in the upward (away from the center of the Earth) direction? Answer: A 10-cm long solenoid is constructed out of 7744.7 turns of copper wire with a total resistance of 62.2 ohms. What is the magnitude of the magnetic field at the center of the solenoid, in teslas, if a potential of 6.8 Volts is applied across the solenoid? Answer:

Explanation / Answer

a. magnetic force F = qVB

F = 866.2* v * 0.45 *10^-6

F = 0.389 *10^-3 * v Newtons

so we need velocity to find force

b. current i = V/R = 6.8 /62.2 =0.109 Amps

Magnetic field due to solonoid B = uo ni

B = 4pi *10^-7 * 7744.7* 0.109

B = 1.06 mT

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