If a person breathers 10 Liters per minute of air at 68 degree F and 50% relativ

Question

If a person breathers 10 Liters per minute of air at 68 degree F and 50% relative humidity , how much water per day must the internal membranes supply to saturate the air at 98.6 degree F? (Assume all the moisture is exhaled) If each gram of water extracts 580 calories as it is vaporized, how much daily heat loss in Kilocalories ( food calories) does this represent? (Saturation vapor pressure at 20 degrees C is 17.3 g/m cubed and at 37 degrees C is 44.0 g/m cubed ( grams per cubic meter).

* Water per day (             ) ans.

(        ) g/day

(        )Liters/day

Energy per day lost (       ) ans.

Please help me on solving this ....

Explanation / Answer

l0 liters / min = 600 l / hr = 14,400 l /day

68 F = 20 C & 98.6 F = 37 C


Total volume exchanged per day is
V = 14.400L/d = 14.4m

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