A water balloon slingshot launches its projectiles essentially from ground level

Question

                    A water balloon slingshot launches its projectiles essentially from ground level at a speed of 25.0m/s . (You can                     ignore air resistance.)                 

                    Its angle to achieve max velocity is 45 degrees although I do not understand the trig it makes perfect sense...
                

HOW LONG WILL THE BALLOON BE IN THE AIR?

For how many seconds will the balloon be in the air?

Explanation / Answer

t = 2*V sin 45 / g = 2*25* sin 45 / 9.8 = 3.607 s

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