The isotope Na 24 (T 1/2 = 15.0 hr ) can be produced by bombarding a Na 23 targe

Question

The isotope Na 24 (T 1/2 = 15.0 hr ) can be produced by bombarding a Na 23 target with

deuterons. The reaction is

If the yield of Na24 , i.e., the number of Na24 atoms produced per second multiplied by

the decay constant, is 100

The isotope Na 24 (T 1/2 = 15.0 hr ) can be produced by bombarding a Na 23 target with deuterons. The reaction is Na23 + H2 rightarrow Na24 + H1 If the yield of Na24 , i.e., the number of Na24 atoms produced per second multiplied by the decay constant, is 100 mu Curies hr, then: What is the activity of the Na24 after a 5 hr bombardment? (t will = 0 here for Na24) If the bombardment is ceased after 5 hr, what is the activity 10 hr later? (t=10 here for Na24) What is the maximum possible activity (the saturation activity) of Na24 in the target?

Explanation / Answer

Part (a):

We have:

T(1/2) = 15.0 hr

lambda = decay constant = ln(2)/(T(1/2)) = 0.69315/15 = 0.04621 hr^_1

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We have: "the number of Na24 atoms produced per second multiplied by the decay constant, is 100

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