HELP PLEASE:)!!!!!!! In the figure below, a uniformly charged disk (radius R and

Question

HELP PLEASE:)!!!!!!!
In the figure below, a uniformly charged disk (radius R and surface charge density +1.10

In the figure below, a uniformly charged disk (radius R and surface charge density +1.10 mu C/m2) lies in the xy plane with its center at the origin. The marked point P is exactly a distance R above the center of the disk. An electron is to be released from rest at several points along the z axis. What is the electron's initial acceleration if it is released at point P? m/s2 if it is released (1/100)th of the way from the disk to point P? m/s2 if it is released (1/1000)th of the way from the disk to point P? m/s2

Explanation / Answer

a)

E = 2 pi k sigma (1 - (z)/(z^2+R^2)^(1/2))

E = 2*3.1416*8.99e9*1.10e-6 * (1 - (R)/(R^2+R^2)^0.5)

E = 2*3.1416*8.99e9*1.10e-6 * (1 - 1/sqrt(2))

E = 18199 N/C

F = q E

a = F/m = q E/m = (-1.6e-19)*18199/(9.109e-31) = -3.20 x 10^15 m/s2 k^

b)

E = 2 pi k sigma (1 - (z)/(z^2+R^2)^(1/2))

E = 2*3.1416*8.99e9*1.10e-6 * (1 - (0.01 R)/((0.01R)^2+R^2)^0.5)

E = 2*3.1416*8.99e9*1.10e-6 * (1 - 0.01/(0.0001+1)^0.5)

E = 61513 N/C

F = q E

a = F/m = q E/m = (-1.6e-19)*61513/(9.109e-31) = -1.08 x 10^16 m/s2

c)

E = 2 pi k sigma (1 - (z)/(z^2+R^2)^(1/2))

E = 2*3.1416*8.99e9*1.10e-6 * (1 - (0.001 R)/((0.001R)^2+R^2)^0.5)

E = 2*3.1416*8.99e9*1.10e-6 * (1 - 0.001/(0.000001+1)^0.5)

E = 62072 N/C

F = q E

a = F/m = q E/m = (-1.6e-19)*62072/(9.109e-31) = -1.09 x 10^16 m/s2

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